What is the probability of getting a sum 9 from two throws of a dice?
In two throws of a dice, $ n \left(S\right)$ = $(6 \times 6)$ = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
$\therefore P\left(E\right)$ =$ \dfrac{n(E)}{n(S)} $=$ \dfrac{4}{36} $=$ \dfrac{1}{9} $.
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