The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:
Let the numbers be 2 x and 3 x .
Then, their L.C.M. = 6 x .
So, 6 x = 48 or x = 8.
$\therefore$ The numbers are 16 and 24.
Hence, required sum = $\left(16 + 24\right)$ = 40.
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