In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:
A : B = 100 : 80.
A : C = 100 : 72.
$\therefore \dfrac{B}{C} $=$ \left(\dfrac{B}{A} \times\dfrac{A}{C} \right) $=$ \left(\dfrac{80}{100} \times\dfrac{100}{72} \right) $=$ \dfrac{10}{9} $=$ \dfrac{100}{90} $= 100 : 90.
$\therefore$ B can give C 10 points.
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