$\left(11111011\right)_{2}$ = $\left(\right)_{8}$
$\left(11111011\right)_{2}$ =$ \left(251\right)_{10}$= $\left(373\right)_{10}$
or
You can group 3 binary digits from right hand side and write their equivalent octal form.
$\left(11111011\right)_{2}$ = $\left(\right)_{8}$
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