If [$x^{1/3}$] - [$x^{1/9}$] = 60 then find the value of x.
Let t = $x^{1/9}$
So,
t3-t=60
Therefore, (t-1) x t x (t + 1) = 60 =3 x 4 x 5.
therefore, t = $x^{1/9}$ =4.
hence, x = $4^9$
If [$x^{1/3}$] - [$x^{1/9}$] = 60 then find the value of x.
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