[4 days] If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2

For Competitive Exams

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

4 days

5 days

6 days

7 days

Explanation:

Let 1 mans 1 days work = x and 1 boys 1 days work = y.
Then, 6x + 8y = 1/10 and 26x + 48y = 1/2 .
Solving these two equations, we get : x = 1/100 and y = 1/200 .
(15 men + 20 boy)s 1 days work = 15/100 + 20/200 = 1/4 .
15 men and 20 boys can do the work in 4 days.

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