If 9x2+3px+6q when divide by 3x+1 leaves a remainder -3/4 and qx2+4px+7 is exactly divisible by x+1, then the values of p and q respectively will be:
0, 7/4
-7/4, 0
Same
7/4, 0
Additional Questions
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The equations 2x+3y-7=0 and 10x+15y-35=0 are: |
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The solution of the simultaneous equations (1/2)x + (1/3)y = 2 and x+y=1 is: |
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If the equation x2-2(k+1)x+(9/2)k=0 has two identical roots then the values of k are: |
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The number which should be subtracted from 5a2-3ab+7b2 to make it equal to a2+ab+b2, is: |
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If x = (1/2) (2p+2q-r), y = (1/3) (-p-2q+3r) and z=(1/5) (3p-4r+5q), then the value of 2x-3y-5z is: |
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The roots of the quadratic equation 6x2-5x+1=0 are: |
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If a = 16, b=25, the value of 1/(a-1/2 - b-1/2) is: |
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3a2 (ab+bc+ca) = |
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x4y-xy4 = |
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Factors of 6a2-25a+4 are: |
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