What was the day of the week on 2nd March, 1602?
Given that,
4th June, 2002 = (Odd days in 1600 years+ 1601 years + period from 1st jan, 1602 to 2nd March, 1602)
Odd days in 1600 years=0
Odd days in 1601 year = 1
Number of days according to the months are
January = 31 days
February = 28 days
March = 2 days
Therefore, 31 + 28 + 2=30 = 4 weeks 2 days ≡ 2 odd day
Total number of odd days = 1 + 2 = 3
Therefore, required day is Wednesday.