$log_{2} 64$
Exponential form: $b^{y}$ = x
Logarithm form: $log_{b} (x)$ = y
Given: $log_{2} 64$
Let the solution of $log_{2} 64$ be y.
$Log_{2} 64$ = y
$2^{y}$ = 64
$2^{6}$ = 64
Therefore, y = 6
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