[\dfrac{C}{x}] The gravitational field due to a mass distribution is I= \\dfrac{C}{x^{2}} in x direction. Here, C

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The gravitational field due to a mass distribution is I= $\\dfrac{C}{x^{2}}$ in x direction. Here, C is constant.
Taking the gravitational potential to be zero at infinity, potential at x is:

$\dfrac{2C}{x}$

$\dfrac{C}{x}$

$\dfrac{2C}{x^2}$

$\dfrac{C}{2x^2}$

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