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If log10 (87.5) = 1.9421, then the number of digits in (875)^10 is?

30
28
33
39
Explanation:

X = (875)^10 = (87.5 x 10)^10
Therefore, log10(X) = 10(log10(87.5 + 1))
= 10(1.9421 + 1)
= 10(2.9421) = 29.421
X = antilog(29.421)
Therefore, number of digits in X = 30.

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