If a number is 20% more than the another, how much % is the smaller number less than the first ?
Take a number 100,
Then the other number is 120
% the smaller number is less than the first = [(20/(120)) x 100]% = 16(2/3)%.
If a number is 20% more than the another, how much % is the smaller number less than the first ?
Take a number 100,
Then the other number is 120
% the smaller number is less than the first = [(20/(120)) x 100]% = 16(2/3)%.
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