[3] If \left(\dfrac{7}{12}\right)^{-4} \times \left(\dfrac{7}{12}\right)^{3x} = \left(\dfrac{5}{12}\r

For Competitive Exams

If $\left(\dfrac{7}{12}\right)^{-4} \times \left(\dfrac{7}{12}\right)^{3x}$ = $\left(\dfrac{5}{12}\right)^{5}$ then the value of x is

- 1

Explanation:
Formula:
$a^{m}\times a^{n}=a^{m+n}$
$=>(\dfrac{7}{12})^{-4+3x}=(\dfrac{7}{12})^{5}$
=>-4+3x=5
3x=5+4
3x=9
x=3

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