41904.If a certain computer is capable of printing 4900 monthly credit card bills per hour, while a new model is capable of printing at a rate of 6600 per hour, the old model will take approximately how much longer than the new model to print 10000 bills?
31 minutes
33 minutes
49 minutes
66 minutes
Explanation:
Old model is capable of printing at a rate of 4900 per hour
New model is capable of printing at a rate of 6600 per hour
Old model time taken to print 10000 cards = 10000/4900 = 100/49
New model time taken to print 10000 cards = 10000/6600 = 100/66
Old model – new model: 100/49 - 100/66 = 1700 /(49 × 66) = 850/(49 × 33) = 0.525 hrs => 31 mins
Therefore, the old model will take approximately 31 mins longer than the new model to print 10000 bills
Old model is capable of printing at a rate of 4900 per hour
New model is capable of printing at a rate of 6600 per hour
Old model time taken to print 10000 cards = 10000/4900 = 100/49
New model time taken to print 10000 cards = 10000/6600 = 100/66
Old model – new model: 100/49 - 100/66 = 1700 /(49 × 66) = 850/(49 × 33) = 0.525 hrs => 31 mins
Therefore, the old model will take approximately 31 mins longer than the new model to print 10000 bills
41905.3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 4 men and 5 women will do that task.
5/6
6/13
7/9
13/14
Explanation:
3 m + 8 w = 6 m + 2 w
3 m = 6 w
1 m = 2 w
Therefore 3 m + 8 w = 14 w
4 m + 5 w =13 w
Answer is 13/14
3 m + 8 w = 6 m + 2 w
3 m = 6 w
1 m = 2 w
Therefore 3 m + 8 w = 14 w
4 m + 5 w =13 w
Answer is 13/14
41906.How can a cake(circular) be cut into 8 pieces by making just 3 cuts?
three mutually perpendicular planes
three mutually horizontal planes
three mutually vertical planes
two mutually vertical planes
Explanation:
Cut the cake using three mutually perpendicular planes. It leaves 8 pieces, one each in each octant.
Cut the cake using three mutually perpendicular planes. It leaves 8 pieces, one each in each octant.
41907.A number of cats got together and decided to kill between them 999919 mice. Every cat killed an equal number of mice. Each cat killed more mice than there were cats. How many cats do you think there were?
990
1000
991
1001
Explanation:
999919 = 1000000 – 81 =10002 – 92 = (1000 + 9)(1000 – 9) = 1009 × 991.
Since there were more mice than there were cats, 991 cats killed 1009 mice each.
999919 = 1000000 – 81 =10002 – 92 = (1000 + 9)(1000 – 9) = 1009 × 991.
Since there were more mice than there were cats, 991 cats killed 1009 mice each.
41908.An alloy of zinc and copper contains the metals in the ratio 5 : 3. The quantity of zinc to be added to 6 kg of the alloy so that the ratio of the metal may be 3 : 1 is:
3
6
8
9
Explanation:
In sixteen kg of alloy 10 kg of zinc and 6 kg copper is present
To make the ratio 3:1 we must add 8 kg of zinc to make it 18 kg of zinc and 6 kg copper
So answer is 8.
In sixteen kg of alloy 10 kg of zinc and 6 kg copper is present
To make the ratio 3:1 we must add 8 kg of zinc to make it 18 kg of zinc and 6 kg copper
So answer is 8.
41909.A class consists of 100 students, 25 of them are girls and 75 boys; 20 of them are rich and remaining poor; 40 of them are fair complexioned. The probability of selecting a fair complexioned rich girl is
3/50
1/50
2/50
1/60
Explanation:
The probability of selecting girl is: 25/100 = 1/4
The probability of selecting rich is: 20/100 = 1/5
The probability of selecting fair complexioned is: 40/100 = 2/5
Three are independent;probability of rich and fair complexioned girl is:
(1/4) ×(1/5) × (2/5) = 1/50
The probability of selecting girl is: 25/100 = 1/4
The probability of selecting rich is: 20/100 = 1/5
The probability of selecting fair complexioned is: 40/100 = 2/5
Three are independent;probability of rich and fair complexioned girl is:
(1/4) ×(1/5) × (2/5) = 1/50
41910.If one-third of one-fourth of a number is 15, then three-tenth of that number is:
35
36
45
54
Explanation:
The number is 1/3 of 1/4 is =15 then 1/3 × 1/4 = 15
Number is 180 then 180 × 3/10 = 54
The number is 1/3 of 1/4 is =15 then 1/3 × 1/4 = 15
Number is 180 then 180 × 3/10 = 54
41911.100 oranges are bought at the rate of Rs. 350 and sold at the rate of Rs. 48 per dozen. The percentage of profit or loss is:
100/7% gain
15% gain
100/7% loss
15 % loss
Explanation:
C.P. of 100 orange=350
S.P. of 12 is 48 i.e, 4 of each now of 100 will be 400
So profit = 400 – 350 = 50
profit = $\dfrac{profit×100%}{cp}$ i.e 100/7% gain
C.P. of 100 orange=350
S.P. of 12 is 48 i.e, 4 of each now of 100 will be 400
So profit = 400 – 350 = 50
profit = $\dfrac{profit×100%}{cp}$ i.e 100/7% gain
41912.If 3/p = 6 and 3/q = 15 then p – q = ?
1/3
2/5
3/10
5/6
Explanation:
$\dfrac{3}{p}$=6, p = $\dfrac{3}{6}=\dfrac{1}{2}$ and
$\dfrac{3}{q}=15$ ,q=$\dfrac{3}{15}=\dfrac{1}{5}$ then
p – q = 1/2 – 1/5 = 3/10
$\dfrac{3}{p}$=6, p = $\dfrac{3}{6}=\dfrac{1}{2}$ and
$\dfrac{3}{q}=15$ ,q=$\dfrac{3}{15}=\dfrac{1}{5}$ then
p – q = 1/2 – 1/5 = 3/10
41913.Two trains leaving from two station 50 miles away from each other with constant speed of 60 miles per hour, approaches towards each other on different tracks. if length of each train is 1/6 mile. when they meet How much time they need to pass each other totally ?
15 seconds
25 seconds
10 seconds
5 seconds
Explanation:
The trains are coming towards each other so their relative speed is 60 + 60 = 120 mph
In this case the distance would be addition of lengths of trains.i.e 1/6 + 1/6 = 1/3 m
T =$\dfrac{d}{s}=\dfrac{1/3}{120}=\dfrac{1}{1360}h$
The trains are coming towards each other so their relative speed is 60 + 60 = 120 mph
In this case the distance would be addition of lengths of trains.i.e 1/6 + 1/6 = 1/3 m
T =$\dfrac{d}{s}=\dfrac{1/3}{120}=\dfrac{1}{1360}h$
41914.There are two bags A and B. A contains 6 red flowers and 3 pink flowers. where as bag B contains 2 red flowers and 7 pink flowers. One flower is chosen from a bag randomly. What is the probability that the flower chosen is pink?
4/9
1/3
5/4
5/9
Explanation:
Bag A 6 red + 3 pink
Bag B 2 red + 7 pink
Probability of picking 1 pink from bag A is 3/9
Probability of picking 1 pink from bag B is 7/9
Total = 3/9 + 7/9 = 10/9
And probability of selecting a bag is 1/2
So finally probability of choosing a pink flower = 1/2(10/9) = 5/9
Bag A 6 red + 3 pink
Bag B 2 red + 7 pink
Probability of picking 1 pink from bag A is 3/9
Probability of picking 1 pink from bag B is 7/9
Total = 3/9 + 7/9 = 10/9
And probability of selecting a bag is 1/2
So finally probability of choosing a pink flower = 1/2(10/9) = 5/9
41915.The sum of a number and its square is 1406. What is the number?
38
39
37
29
Explanation:
By option Verification 37 + 37 × 37 = 1406
By option Verification 37 + 37 × 37 = 1406
41916.How many 4-letter words with or without meaning, can be formed out of the letters of the word, LOGARITHMS, if repetition of letters is not allowed?
40
400
5040
2520
Explanation:
The Word LOGARITHMS is contain 10 letters.
To find how many 4 letter word we can find from that = 10 × 9 × 8 × 7 = 5040.
The Word LOGARITHMS is contain 10 letters.
To find how many 4 letter word we can find from that = 10 × 9 × 8 × 7 = 5040.
41917.At 6′o a clock ticks 6 times. The time between first and last ticks is 30 seconds. How long does it tick at 12′o clock
40
70
66
56
Explanation:
For ticking 6 times, there are 5 intervals.
Each interval has time duration of 30/5 = 6 secs
At 12 oclock, there are 11 intervals,
So total time for 11 intervals = 11 × 6 = 66 secs.
For ticking 6 times, there are 5 intervals.
Each interval has time duration of 30/5 = 6 secs
At 12 oclock, there are 11 intervals,
So total time for 11 intervals = 11 × 6 = 66 secs.
41918.A man travelled from the village to the post-office at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village
40 km
20 km
66 km
25 km
Explanation:
Average speed = (2 ×a × b)/(a + b) here a = 25 b = 4
Average speed = 2 × 25 × 4/(25 + 4) = 200/29 kmph.
Distance covered in 5 hours 48 minutes = Speed × time
Distance = (200/29) × (29/5) = 40 kms
Distance covered in 5 hours 48 minutes = 40 kms
Distance of the post office from the village = (40/2) =20 km.
Average speed = (2 ×a × b)/(a + b) here a = 25 b = 4
Average speed = 2 × 25 × 4/(25 + 4) = 200/29 kmph.
Distance covered in 5 hours 48 minutes = Speed × time
Distance = (200/29) × (29/5) = 40 kms
Distance covered in 5 hours 48 minutes = 40 kms
Distance of the post office from the village = (40/2) =20 km.
41919.One year payment to the servant is Rs. 200 plus one shirt. The servant leaves after 9 months and receives Rs. 120 and a shirt.Then find the price of the shirt.
140
120
166
200
Explanation:
12 months == Rs 200 + shirt --(1)
9 months == Rs 120 + shirt --(2)
After subtracting equation (2) from (1) we get,(shirt is cancelled)
3 months = Rs 80
12 months = (80 × 12)/3= 320
Hence from equation (1) we get 320 = 200 + shirt
Therefore shirt = 120 Rs/-
12 months == Rs 200 + shirt --(1)
9 months == Rs 120 + shirt --(2)
After subtracting equation (2) from (1) we get,(shirt is cancelled)
3 months = Rs 80
12 months = (80 × 12)/3= 320
Hence from equation (1) we get 320 = 200 + shirt
Therefore shirt = 120 Rs/-
41920.In a class there are 45 pupil, out of them 12 are in debate only and 22 in singing only. Then how many in both?
14
12
16
11
Explanation:
Total pupil = 45
Debate + Singing = 12 + 22 = 34
The intersection for two = 45 – 12 – 22 = 11 play both games.
Total pupil = 45
Debate + Singing = 12 + 22 = 34
The intersection for two = 45 – 12 – 22 = 11 play both games.
41921.Silu and Meenu were walking on the road.
Silu said, "I weigh 51 Kgs. How much do you weigh?"
Meenu replied that she wouldnt reveal her weight directly as she is overweight.
But she said, "I weigh 29 Kgs plus half of my weight."How much does Meenu weigh?
Silu said, "I weigh 51 Kgs. How much do you weigh?"
Meenu replied that she wouldnt reveal her weight directly as she is overweight.
But she said, "I weigh 29 Kgs plus half of my weight."How much does Meenu weigh?
58
29
50
20
Explanation:
It is given that Meenu weighs 29 Kgs plus half of her own weight.
It means that 29 Kgs is the other half. So she weighs 58 Kgs.
Solving mathematically, lets assume that her weight is A Kgs.
A = 29 + A/2
2 × A = 58 + A
A = 58 Kgs.
It is given that Meenu weighs 29 Kgs plus half of her own weight.
It means that 29 Kgs is the other half. So she weighs 58 Kgs.
Solving mathematically, lets assume that her weight is A Kgs.
A = 29 + A/2
2 × A = 58 + A
A = 58 Kgs.
41922.What is the 56743 rd term in the series 1234567891011121314…….?
1
3
7
5
Explanation:
1 to 9 = 9 no.s 1 digit each no.
9 to 99 = 90 no.s 2 digit each,Total digit = 90 × 2 = 180 terms
99 to 999 = 900 no.s 3 digit each,total digit = 900 × 3 = 2700
999 to 9999 = 9000 no.s 4 digit each,total digit = 9000 × 4 = 36,000
Till Now 999,we have = 9 + 180 + 2700 = 2889 digits
Upto 9999 we have = 2889 + 36000 = 38889 digits
56743 – 38889 = 17854
After 9999 each no. has 5 digit
So 17584/5= 3570 with remainder 4.
3570th no after 9999 =9999+3570=13569
Next term=13570.
4th digit =7 so answer=7
1 to 9 = 9 no.s 1 digit each no.
9 to 99 = 90 no.s 2 digit each,Total digit = 90 × 2 = 180 terms
99 to 999 = 900 no.s 3 digit each,total digit = 900 × 3 = 2700
999 to 9999 = 9000 no.s 4 digit each,total digit = 9000 × 4 = 36,000
Till Now 999,we have = 9 + 180 + 2700 = 2889 digits
Upto 9999 we have = 2889 + 36000 = 38889 digits
56743 – 38889 = 17854
After 9999 each no. has 5 digit
So 17584/5= 3570 with remainder 4.
3570th no after 9999 =9999+3570=13569
Next term=13570.
4th digit =7 so answer=7
41923.A cycled from P to Q at 10 kmph and returned at the rate of 9 kmph. B cycled both ways at 12 kmph. In the whole journey B took 10 minutes less than A. Find the distance between P and Q.
10 km
3 km
3.75 km
12 km
Explanation:
Let the distance between P and Q = d km
A - time = d/10 + d/9 = 19 d/90 hours
B - time = 2 d/12 = d/6 hours
10 minutes = 1/6 hours
Thus 19 d/90 – d/6 = 1/6
(19 d – 15 d)/90 = 1/6
4 d/90 = 1/6
thus d = 15/4 km = 3.75 km
Let the distance between P and Q = d km
A - time = d/10 + d/9 = 19 d/90 hours
B - time = 2 d/12 = d/6 hours
10 minutes = 1/6 hours
Thus 19 d/90 – d/6 = 1/6
(19 d – 15 d)/90 = 1/6
4 d/90 = 1/6
thus d = 15/4 km = 3.75 km