Rohit was 4 times as old as his son 8 years ago. After 8 years, Rohit will be twice as old as
his son. What are their present ages?
40
45
42
43
Explanation:
Let sons age 8 years ago be x years. Then, Rohits age 8 years ago = 4x years.
Sons age after 8 years = (x + 8) + 8 = (x + 16) years.
Rohits age after 8 years = (4x + 8) + 8 = (4x+ 16) years.
2 (x + 16) = 4x + 16
2x = 16 => x = 8.
Hence, sons present age = (x + 8) = 16 years.
Rohits present age = (4x + 8) = 40 years
Let sons age 8 years ago be x years. Then, Rohits age 8 years ago = 4x years.
Sons age after 8 years = (x + 8) + 8 = (x + 16) years.
Rohits age after 8 years = (4x + 8) + 8 = (4x+ 16) years.
2 (x + 16) = 4x + 16
2x = 16 => x = 8.
Hence, sons present age = (x + 8) = 16 years.
Rohits present age = (4x + 8) = 40 years