The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Let the numbers be 37$ a $ and 37$ b $.
Then, 37$ a $ x 37$ b $ = 4107
$\Rightarrow$ ab = 3.
Now, co-primes with product 3 are $\left(1, 3\right)$.
So, the required numbers are $\left(37 \times 1, 37 \times 3\right)$ i.e., $\left(37, 111\right)$.
$\therefore$ Greater number = 111.
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