The sides of 14 Squares are 11 cm, 12 cm, 13 cm, .......... 24 cm, then find the total area of 14 squares.
$\dfrac{n(n+1)(2n+1)}{6}$
$Area of square=a^{2}$
$11^{2}+12^{2}+13^{2}+...+24^{2}$
$=[1^{2}+2^{2}+3^{2}+....+24^{2}]-[1^{2}+2^{2}+3^{2}+...+10^{2}]$
$=\dfrac{24\times25\times49}{6}-\dfrac{10\times11\times21}{6}$
$=4900-385$
$=4515$
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A and B can complete a work individually in 12 days and 18 days. They started doing the work together but after 4 days. A had to leave and B alone completed the remaining work. The whole work was completed in |
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A function f:(-7,6) $\Rightarrow$ R is defined as follows |
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