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The slant height of a right circular cone is 10 m and its height is 8 m. Find the area of its curved surface.

$30 \pi m^2$
$40 \pi m^2$
$60 \pi m^2$
$80 \pi m^2$
Explanation:

l = 10 m,

h = 8 m.

So, $r = \sqrt{l^2 - h^2} = \sqrt{(10)^2 - (8)^2} = 6m$

ஃ Curved surface area =$ \pi rl = (\pi \times 6 \times 10) m^2 = 60 \pi m^2.$

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