[36] A tap takes 36 hours extra to fill a tank due to a leakage equivalent to half of its inflow. The inf

For Competitive Exams

A tap takes 36 hours extra to fill a tank due to a leakage equivalent to half of its inflow. The inflow can fill in how many hours?

Explanation:

Let inflow alone can fill the tank in x hours.
Then, the leak alone can empty the tank in 2x hours.
Part filled by the inflow in 1 hour =$\dfrac{1}{x}$
Part emptied by the leak in 1 hour =$\dfrac{1}{2x}$
Net part filled by the inflow and the leak in 1 hour =$\dfrac{1}{x+36}$
$\dfrac{1}{x}−\dfrac{1}{2x}=\dfrac{1}{x+36}$
⇒$\dfrac{1}{2x}=\dfrac{1}{x+36}$
⇒2x=x+36
⇒x=36

Additional Questions

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