The value of $\dfrac{1.75×1.75+2×1.75×0.75+0.75×0.75}{1.75 x 1.75- 0.75 x 0.75}$
3.5
6.25
1
2.5
Explanation:
the given question is in format of =$\dfrac{(a+b)^{2}}{a^{2}-b^{2}}$
therefore,=$\dfrac{(a+b)\times (a+b)}{(a+b) (a-b)}$
=$\dfrac{(a+b)}{(a-b)}$
ie.,=$\dfrac{1.75+0.75}{1.75-0.75}$
=2.5/1=2.5
the given question is in format of =$\dfrac{(a+b)^{2}}{a^{2}-b^{2}}$
therefore,=$\dfrac{(a+b)\times (a+b)}{(a+b) (a-b)}$
=$\dfrac{(a+b)}{(a-b)}$
ie.,=$\dfrac{1.75+0.75}{1.75-0.75}$
=2.5/1=2.5