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The diagonal of the floor of a rectangular closet is 7$ \dfrac{1}{2} $ feet. The shorter side of the closet is 4$ \dfrac{1}{2} $ feet. What is the area of the closet in square feet?

5 $ \frac{1}{4} $
13 $ \frac{1}{2} $
27
37
Explanation:
Other side = $ \sqrt{\left(\dfrac{15}{2} \right)^2-\left(\dfrac{9}{2} \right)^2} $ ft
= $ \sqrt{\dfrac{225}{4} -\dfrac{81}{4} } $ ft
= $ \sqrt{\dfrac{144}{4} } $ ft
= 6 ft.

$\therefore$ Area of closet = $\left(6 \times 4.5\right)$ sq. ft = 27 sq. ft.

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