The current of a stream runs at the rate of 2 km per hr. A motor boat goes 10 km upstream and back again to the starting point in 55 min. Find the speed of the motor boat in still water?
Let the speed of the boat in still water $=x$ km/hr
Speed of the current = 2 km/hr
Then, speed downstream $=\left(x+2\right)$ km/hr
speed upstream $=\left(x-2\right)$ km/hr
Total time taken to travel 10 km upstream and back = 55 minutes $=\dfrac{55}{60}$ hour = $\dfrac{11}{12}$ hour
$\Rightarrow \dfrac{10}{x-2} + \dfrac{10}{x+2} = \dfrac{11}{12}$
$120\left(x+2\right) + 120\left(x-2\right) = 11\left(x^2-4\right)$
$240x = 11x^2 - 44$
$11x^2 - 240x - 44 = 0$
$11x^2 - 242x +2x - 44 = 0$
$11x\left(x-22\right)+2\left(x-22\right)=0 $
$ \left(x-22\right)(11x+2)=0$
$x=22\text{ or }\dfrac{-2}{11}$
Since $x$ cannot be negative, $x$ = 22
i.e., speed of the boat in still water = 22 km/hr