$\dfrac{4.2 \times 4.2 - 1.9 \times 1.9}{2.3 \times 6.1}$ is equal to :
Given Expression =$\dfrac{(a^2 - b^2)}{(a+b)(a-b)}$=$\dfrac{(a^2 - b^2)}{(a^2 - b^2)}$=1
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The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ? |
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Which of the following fractions is greater than $\dfrac{3}{4}$ and less than $\dfrac{5}{6}$ ? |
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The value of $\dfrac{489.1375 \times 0.0483 \times 1.956}{0.0873 \times 92.581 \times 99.749}$ is closest to: |
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The least among the following is: |
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$\dfrac{5\times1.6 - 2 \times 1.4}{1.3}$=? |
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How many digits will be there to the right of the decimal point in the product of 95.75 and .02554 ? |
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The expression (11.98 $\times$ 11.98 + 11.98 $\times$ x + 0.02 $\times$ 0.02) will be a perfect square for $x$ equal to: |
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$\dfrac{(0.1667)(0.8333)(0.3333)}{(0.2222)(0.6667)(0.1250)}$ is approximately equal to: |
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3889 + 12.952 - ? = 3854.002 |
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$\dfrac{4.2 \times 4.2 - 1.9 \times 1.9}{2.3 \times 6.1}$ is equal to : |
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