[4] The least number of complete years in which a sum of money put out at 20% compound interest will be

For Competitive Exams

The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is:

Explanation:

P$ \left(1 +\dfrac{20}{100} \right)^ n $> 2P $\Rightarrow$ $ \left(\dfrac{6}{5} \right)^n $> 2.

Now,$ \left(\dfrac{6}{5} \times\dfrac{6}{5} \times\dfrac{6}{5} \times\dfrac{6}{5} \right) $> 2.

So, $ n $ = 4 years.

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