18 men bind 900 books in 10 days. Find how many binders will be required to bind 600 books in 12 days?
We have to find the number of binders. Let the number of binders be x.
Direct Proportion:Less Books ($\downarrow$),Less binders($\downarrow$)
Indirect Proportion:More days ($\uparrow$),Less binders ($\downarrow$)
18 : x :: $\begin{cases}900 &: 600---(books) \\12 &: 10---(days) \end{cases}$
x × 900 × 12 = 18 × 600 × 10
x = $\dfrac{18\times 600 \times 10}{900 \times 12}$ = 10