[10^\circ] The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:

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The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:

0$^\circ$

10$^\circ$

5$^\circ$

20$^\circ$

Explanation:

Angle traced by hour hand in$ \dfrac{13}{3} $hrs =$\left(\dfrac{360}{12}\times\dfrac{13}{3}\right)^\circ$= 130$^\circ$

Angle traced by min. hand in 20 min. =$ \left(\dfrac{360}{60} \times 20\right)^\circ $= 120$^\circ$.

$\therefore$ Required angle = (130 - 120)$^\circ$ = 10$^\circ$.

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