[7 + \dfrac{817}{1020}] 9+\dfrac{3}{4}+7+\dfrac{2}{17}-\left(9+\dfrac{1}{15}\right)=?

For Competitive Exams

9+$\dfrac{3}{4}$+7+$\dfrac{2}{17}$-$\left(9+\dfrac{1}{15}\right)$=?

7 +$ \dfrac{719}{1020} $

9 +$ \dfrac{817}{1020} $

9 +$ \dfrac{719}{1020} $

7 +$ \dfrac{817}{1020} $

Explanation:

Given sum

= 9 +$ \dfrac{3}{4} $+ 7 +$ \dfrac{2}{17} $-$ \left(9 +\dfrac{1}{15} \right) $

= (9 + 7 - 9) +$ \left(\dfrac{3}{4} +\dfrac{2}{17} -\dfrac{1}{15} \right) $

= 7 +$ \dfrac{765 + 120 - 68}{1020} $

= 7 +$ \dfrac{817}{1020} $

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