[n is any natural number] (xn - an) is completely divisible by (x

For Competitive Exams

(xⁿ - aⁿ) is completely divisible by (x - a), when

n is any natural number

n is an even natural number

n is and odd natural number

n is prime

Explanation:

For every natural number $ n $, (x ^{$ n $} - $ a $^{$ n $}) is completely divisible by (x - a).

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