Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Required number = H.C.F. of $\left(91 - 43\right)$, $\left(183 - 91\right)$ and $\left(183 - 43\right)$
= H.C.F. of 48, 92 and 140 = 4.
|
Three numbers which are co-prime to each other are such that the product of the first two is 119 and that of the last two is 391. What is the sum of the three numbers? |
Answer |
|
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: |
Answer |
|
Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is: |
Answer |
|
The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: |
Answer |
|
What is the greatest number which divides 24, 28 and 34 and leaves the same remainder in each case? |
Answer |
|
The greatest number of four digits which is divisible by 15, 25, 40 and 75 is: |
Answer |
|
What is the LCM of 2/3,5/6 and 4/9 ? |
Answer |
|
What is the least number which when doubled will be exactly divisible by 12, 14, 18 and 22 ? |
Answer |
|
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. |
Answer |
|
Three numbers which are co-prime to each other are such that the product of the first two is 119 and that of the last two is 391. What is the sum of the three numbers? |
Answer |