A man rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. What is his average speed for the entire trip approximately?
Total distance travelled = 10 + 12 = 22 km
Time taken to travel 10 km at an average speed of 12 km/hr = $\dfrac{distance}{speed} = \dfrac{10}{12}$hr
Time taken to travel 12 km at an average speed of 10 km/hr = $\dfrac{distance}{speed} = \dfrac{12}{10}$hr
Total time taken =$\dfrac{10}{12} + \dfrac{12}{10}$hr
Average speed =$\dfrac{distance}{time}= \dfrac{22 }{\left(\dfrac{10}{12} + \dfrac{12}{10}\right)} = \dfrac{22 \times 120 }{\left(10 \times 10\right) + \left(12 \times 12\right)}$
$\dfrac{22 \times 120 }{244}=\dfrac{11 \times 120 }{122}=\dfrac{11 \times 60}{61}=\dfrac{660}{61}\approx $10.8kmph