A sum of money triples itself at 8% per annum over certain time. The number of years is equal to
n=3 times
$N=\dfrac{(n-1)\times100)}{R}$
$ =\dfrac{(3-1)\times100}{8}$
$ =\dfrac{200}{8}$
$ =25 years$
A sum of money triples itself at 8% per annum over certain time. The number of years is equal to
n=3 times
$N=\dfrac{(n-1)\times100)}{R}$
$ =\dfrac{(3-1)\times100}{8}$
$ =\dfrac{200}{8}$
$ =25 years$
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