[2.1] If A=+, B=\div, C=x, and D= -, then what is the value of \dfrac{1}{5}C2B\frac{1}{5}A\frac{1}{5}

For Competitive Exams

If A=+, B=$\div$, C=x, and D= -, then what is the value of $\dfrac{1}{5}C2B\frac{1}{5}A\frac{1}{5}D\frac{1}{10}=? $

2.1

1.2

2.5

1.6

Explanation:

$Given question becomes,\dfrac{1}{5}\times2\div\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{10}=?$

$=[\dfrac{1}{5}\times2\times\dfrac{5}{1}]+[\dfrac{1}{5}-\dfrac{1}{10}]$

$=2+[\frac{2-1}{10}]$

$=2+\frac{1}{10}$

$=2+0.1$

$=2.1$

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