Average of first five multiples of 3 is
$=\dfrac{3\left(1+2+3+4+5\right)}{5}$
$=\dfrac{45}{5}$
=9
Average of first five multiples of 3 is
$=\dfrac{3\left(1+2+3+4+5\right)}{5}$
$=\dfrac{45}{5}$
=9
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Average of first five multiples of 3 is |
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