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A runs 1 $\dfrac{3}{8}$ times As fast as B. If A gives B a start of 90 m and they reach the goal at the same time. The goal is at a distance of

330 m
440 m
120 m
280 m
Explanation:

Speed of A : Speed of B = $\dfrac{11}{8}$: 1 = 11 : 8

Let Speed of A = 11k

and Speed of B = 8k

Let the distance to the goal = x

Time taken by A = time taken by B

=$\dfrac{Distance\: travelled\:by\: A}{Speed\: of\: A}$=$\dfrac{Distance\: travelled\:by\: B}{Speed\: of\: B}$

= $\dfrac{x}{11k}$= $\dfrac{x-90}{8k}$

= $\dfrac{x}{11}$= $\dfrac{x-90}{8}$

8x=11x-990

3x=990

x=330

Distance to the goal = 330 metre

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