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If ABC and DEF are two triangles and $\dfrac{AB}{DE}=\dfrac{BC}{FD}$, then the two triangles are similar if

$\angle A=\angle F$
$\angle B=\angle D$
$\angle A=\angle D$
$\angle B=\angle E$
Explanation:

If ABC and DEF are two triangles and $\dfrac{AB}{DE}=\dfrac{BC}{FD}$, then the two triangles are similar if $\angle B=\angle D$.

Additional Questions

Which of the following are not similar figures?

Answer

If in two triangles ABC and PQR, $\dfrac{AB}{QR} = \dfrac{BC}{PR} = \dfrac{CA}{PQ}$, then

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Which of the following is not a similarity criterion for two triangles?

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The ratio of the areas of two similar triangles is equal to

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Which of the following triangles have the same side lengths?

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Area of an equilateral triangle with side length a is equal to:

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D and E are the midpoints of side AB and AC of a triangle ABC, respectively and BC = 6 cm. If DE || BC, then the length (in cm) of DE is:

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The diagonals of a rhombus are 16 cm and 12 cm, in length. The side of the rhombus in length is:

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Corresponding sides of two similar triangles are in the ratio of 2:3. If the area of the small triangle is 48 sq.cm, then the area of large triangle is:

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If perimeter of a triangle is 100 cm and the length of two sides are 30 cm and 40 cm, the length of third side will be:

Answer
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