[ΔPQR ~ ΔCAB] If in two triangles ABC and PQR, \dfrac{AB}{QR} = \dfrac{BC}{PR} = \dfrac{CA}{PQ}, then

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Aptitude

TNPSC G4

10th CBSE Maths

If in two triangles ABC and PQR, $\dfrac{AB}{QR} = \dfrac{BC}{PR} = \dfrac{CA}{PQ}$, then

ΔPQR ~ ΔCAB

ΔPQR ~ ΔABC

ΔCBA ~ ΔPQR

ΔBCA ~ ΔPQR

Explanation:

Given that, in triangles ABC and PQR, $\dfrac{AB}{QR} = \dfrac{BC}{PR} = \dfrac{CA}{PQ}$

If sides of one triangle are proportional to the side of the other triangle, and their corresponding angles are also equal, then both the triangles are similar by SSS similarity. Therefore, ΔPQR ~ ΔCAB

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