If a tower 6m high casts a shadow of $2\sqrt{3}$ m long on the ground, then the sun’s elevation is:
As per the given question:
Hence,
tan θ = $\dfrac{6}{2\sqrt{3}}$
tan θ = $\sqrt{3}$
tan θ = tan 60°
⇒ θ = 60°
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If a tower 6m high casts a shadow of $2\sqrt{3}$ m long on the ground, then the sun’s elevation is: |
Answer |