Easy Tutorial
For Competitive Exams

The mode and mean is given by 7 and 8, respectively. Then the median is:

$\dfrac{1}{13}$
$\dfrac{13}{3}$
$\dfrac{23}{3}$
33
Explanation:

Using Empirical formula,

Mode = 3Median – 2 Mean

3Median = Mode + 2Mean

Median = $\dfrac{(Mode + 2Mean)}{3}$

Median = $\dfrac{[7 + 2(8)]}{3} = \dfrac{(7 + 16)}{3} = \dfrac{23}{3}$

Additional Questions

The mean of the data: 4, 10, 5, 9, 12 is;

Answer

The median of the data 13, 15, 16, 17, 19, 20 is:

Answer

If AM of a, a+3, a+6, a+9 and a+12 is 10, then a is equal to;

Answer

The class interval of a given observation is 10 to 15, then the class mark for this interval will be:

Answer

Construction of a cumulative frequency table is useful in determining the

Answer

The abscissa of the point of intersection of the less than type and of the more than type cumulative frequency curves of a grouped data gives its

Answer

While computing mean of grouped data, we assume that the frequencies are

Answer

The method used to find the mean of a given data is(are):

Answer

If $x_1, x_2, x_3,….., x_n$ are the observations of a given data. Then the mean of the observations will be:

Answer

The mode and mean is given by 7 and 8, respectively. Then the median is:

Answer
Share with Friends
Privacy Copyright Contact Us