10915.Find the number of square tiles to cover the floor of a room measuring 4 m $\times$ 9 m leaving 0.25 m space around the room. A side of square tile is given to be 25 cms?
10916.A rectangular farm has to be fenced one long side, one short side and the diagonal. If the cost of fencing is Rs.10 per meter. The area of farm is 1200 m2 and the short side is 30 m long. How much would the job cost?
Rs.700
Rs.1200
Rs.1400
Rs.1500
Explanation:
l $\times$ 30 = 1200 $\rightarrow$ l = 40
$\sqrt{40^2+30^2}$ = 50
40 + 30 + 50 = 120
120 $\times$ 10 = 1200
10917.The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/8 of the area of the field. What is the length of the field?
31 m
32 m
16 m
20 m
Explanation:
A/8 = 8 $\times$ 8 => A = 8 $\times$ 8 $\times$ 8
x $\times 2x$ = 8 $\times$ 8 $\times$ 8
x = 16 => 2x = 32
10918.The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.50 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?
10919.The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?
432 sq m
356 sq m
452 sq m
428 sq m
Explanation:
$2\left(3x + x\right)$ = 96
l = 36 b = 12
lb = 36 $\times$ 12 = 432
10920.A rectangular grass field is 75 m $\times$ 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m?
675, Rs.1350
575, Rs.1350
1350, Rs.675
None
Explanation:
Area =$\left (l + b +2d\right)$ 2d
= (75 + 55 +2.5 $\times$ 2) 2$\times$2.5 => 675
675 $\times$ 2 = Rs.1350
10921.A rectangular lawn of dimensions 80 m $\times$ 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?
Rs.3600
Rs.3700
Rs.3800
Rs.3900
Explanation:
Area = $\left(l + b - d\right)$ d
(80 + 60 - 10)10 => 1300 $m^2$
1300 $\times$ 3 = Rs.3900
10922.The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area?
Remains same
5% decrease
5% increase
10% increase
Explanation:
100 $\times$ 100 = 10000
125 $\times$ 80 = 10000
No change
10923.The side of a rhombus is 26 m and length of one of its diagonals is 20 m. The area of the rhombus is?
529 sq m
240 sq m
260 sq m
480 sq m
Explanation:
$26^2$ � $10^2$ = $24^2$
$d_{1}$ = 20 $d_{2}$ = 48
1/2 $\times$ 20 $\times$ 48 = 480
10924.The diagonals of a rhombus are 15 cm and 20 cm. Find its area?
120 sq m
300 sq m
150 sq m
480 sq m
Explanation:
1/2 $\times$ 15 $\times$ 20 = 150
10925.The perimeter of a rhombus is 68 cm and one of its diagonals is 16 cm. Find its area?
260 $cm^2$
240 $cm^2$
280 $cm^2$
220 $cm^2$
Explanation:
4a = 68 => a = 17
172 - 82 = 152
1/2 $\times$ 16 $\times$ 30 = 240
10926.The area of a parallelogram is 128sq m and its altitude is twice the corresponding base. Then the length of the base is?
8 m
10 m
6 m
12 m
Explanation:
2x $\times$ x = 128 => x= 8
10927.The side of a square is increased by 25% then how much % does its area increases?
52.65
56.25
50.75
42.75
Explanation:
a = 100 $a^2$ = 10000
a = 125 $a^2$ = 15625
----------------
10000 --------- 5625
100 -------? => 56.25 %
10928.The cross-section of a cannel is a trapezium in shape. If the cannel is 10 m wide at the top and 6 m wide at the bottom and the area of cross-section is 640 sq m, the depth of cannel is?
20 m
60 m
40 m
80 m
Explanation:
1/2 $\times$ d (10 + 6) = 640
d = 80
10929.The radius of a circle is increased by 1%. Find how much % does its area increases?
1.01%
5.01%
3.01%
2.01%
Explanation:
r = 100 r = 101
$r^2$ = 10000 $r^2$ = 10201
10000 ---- 201
100 ---- ? => 2.01%
10930.Find the area of the quadrilateral of one of its diagonals is 20 cm and its off sets 9 cm and 6 cm?
