1311.The ages of Krish and Vaibhav are in the proportion of 3 : 5. After 9 years, the proportion of their ages will be 3 : 4. Then the current age of Vaibhav is:
19 years
12 years
10 years
15 years
Explanation:
Krish’s age = 3A and Vaibhav’s age = 5A
(3A+9)/(5A+9) = 3/4
=> 4 (3A + 9) = 3 (5A + 9)
=> A = 3
Therefore, Vaibhav’s age = 15 years.
Krish’s age = 3A and Vaibhav’s age = 5A
(3A+9)/(5A+9) = 3/4
=> 4 (3A + 9) = 3 (5A + 9)
=> A = 3
Therefore, Vaibhav’s age = 15 years.
1312.Sajithas age is one-sixth of her mothers age. Sajithas mothers age will be two times of Karthikhs age after 10 years. If Karthikhs 8-th birthday was celebrated 2 years before, then what is Sajithas current age?
15 years
6(2/3) years
5(1/2) years
12(3/4) years
Explanation:
Karthikh's present age
= (8 + 2) years
= 10 years
Sajitha's father's age
= 2(10 + 10) years
= 40 years
Sajitha's age
= ($\dfrac{1}{6} $×40) years
= $\dfrac{20}{3}$ years
= 6 $\dfrac{2}{3}$years
Karthikh's present age
= (8 + 2) years
= 10 years
Sajitha's father's age
= 2(10 + 10) years
= 40 years
Sajitha's age
= ($\dfrac{1}{6} $×40) years
= $\dfrac{20}{3}$ years
= 6 $\dfrac{2}{3}$years
1313.5 years ago Amith was three times as old as his daughter and 10 years hence, he will be two times as old as his daughter. Then Amiths current age is,
7 years
None of these
55
50
Explanation:
Let the present age of Amit be x.
Let the present age of daughter be y.
Given that 5 years ago Amit was three times as old as daughter.
x - 5 = 3 * (y - 5)
x - 5 = 3y - 15
x = 3y - 10 ------ (1)
Given that ten years later Amit would be twice as old as daughter.
x + 10 = 2(y + 10)
x + 10 = 2y + 20
x = 2y + 10 ---- (2)
On solving (1) and (2), we get
3y - 10 = 2y + 10
3y = 2y + 20
3y - 2y = 20
y = 20 ---- (3)
Substitute (3) in (1), we get
x = 3y - 10
= 3(20) - 10
= 50.
Therefore the present age of Amit is 50.
Let the present age of Amit be x.
Let the present age of daughter be y.
Given that 5 years ago Amit was three times as old as daughter.
x - 5 = 3 * (y - 5)
x - 5 = 3y - 15
x = 3y - 10 ------ (1)
Given that ten years later Amit would be twice as old as daughter.
x + 10 = 2(y + 10)
x + 10 = 2y + 20
x = 2y + 10 ---- (2)
On solving (1) and (2), we get
3y - 10 = 2y + 10
3y = 2y + 20
3y - 2y = 20
y = 20 ---- (3)
Substitute (3) in (1), we get
x = 3y - 10
= 3(20) - 10
= 50.
Therefore the present age of Amit is 50.
1314.Ayesha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
5 years
6 years
1 years
3 years
Explanation:
Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
∴ Required difference = (42 - 36) years = 6 years.
Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
∴ Required difference = (42 - 36) years = 6 years.
1315.A guy was asked to specify his age in years. He said, “Take my age 3 years hence, multiply it by three and subtract thrice of my age 3 years ago and you will know my age.” What was the age of that guy?
5 years
6 years
16 years
18 years
Explanation:
Lets assume his current age is ‘x’.
His age 3 years from now: (x+3)
His age 3 years earlier: (x-3).
As per what is stated, his current age is - 3(x+3) - 3(x-3)
therefore, solve x= 3x + 9 - 3x + 9
The answer is x = 18
c
Lets assume his current age is ‘x’.
His age 3 years from now: (x+3)
His age 3 years earlier: (x-3).
As per what is stated, his current age is - 3(x+3) - 3(x-3)
therefore, solve x= 3x + 9 - 3x + 9
The answer is x = 18
c
1316.What least number must be added to 859622, to get a number exactly divisible by 456?
20 years
22 years
321
394
Explanation:
Dividend = Quotient * Divisor + Reminder
859622 / 456 gives quotient = 1885 and reminder = 62.
So, the next number divisible by 456 is 456 places infront of 456 * 1885
Which means 456 – 62 = 394 should be added to 859622.
Dividend = Quotient * Divisor + Reminder
859622 / 456 gives quotient = 1885 and reminder = 62.
So, the next number divisible by 456 is 456 places infront of 456 * 1885
Which means 456 – 62 = 394 should be added to 859622.
1334.Rajeevs age after 15 years will be 5 times his age 5 years back. What is the present age of Rajeev ?
11
10
12
8
Explanation:
Let Rajeevs present age be x years. Then,
Rajeevs age after 15 years = (x + 15) years.
Rajeevs age 5 years back = (x - 5) years.
Therefore x + 15 = 5 (x - 5)
x + 15 = 5x - 25
4x = 40
x = 10.
Hence, Rajeevs present age = 10 years
Let Rajeevs present age be x years. Then,
Rajeevs age after 15 years = (x + 15) years.
Rajeevs age 5 years back = (x - 5) years.
Therefore x + 15 = 5 (x - 5)
x + 15 = 5x - 25
4x = 40
x = 10.
Hence, Rajeevs present age = 10 years
1335.The ages of two persons differ by 16 years. If 6 years ago, the elder one be 3 times as old
as the younger one, find their present ages.
as the younger one, find their present ages.
14,30
12,36
14,21
16,36
Explanation:
Let the age of the younger person be x years.
Then, age of the elder person = (x + 16) years.
Therefore 3 (x - 6) = (x + 16 - 6)
3x -18 = x + 10
2x = 28
x = 14.
Hence, their present ages are 14 years and 30 years.
Let the age of the younger person be x years.
Then, age of the elder person = (x + 16) years.
Therefore 3 (x - 6) = (x + 16 - 6)
3x -18 = x + 10
2x = 28
x = 14.
Hence, their present ages are 14 years and 30 years.
1336.The product of the ages of Ankit and Nikita is 240. If twice the age of Nikita is more than
Ankits age by 4 years, what is Nikitas age?
Ankits age by 4 years, what is Nikitas age?
10
12
13
15
Explanation:
Let Ankits age be x years. Then, Nikitas age = 240/x years.
2 * (240 /x ) – x = 4
480 – x2 = 4x
x2 + 4x – 480 = 0
( x+24)(x-20) = 0
x = 20.
Hence, Nikitas age = 240/x = 240/20 years = 12 years.
Let Ankits age be x years. Then, Nikitas age = 240/x years.
2 * (240 /x ) – x = 4
480 – x2 = 4x
x2 + 4x – 480 = 0
( x+24)(x-20) = 0
x = 20.
Hence, Nikitas age = 240/x = 240/20 years = 12 years.
1337.The present age of a father is 3 years more than three times the age of his son. Three
years hence, fathers age will be 10 years more than twice the age of the son. Find the
present age of the father.
years hence, fathers age will be 10 years more than twice the age of the son. Find the
present age of the father.
33
35
31
32
Explanation:
Let the sons present age be x years. Then, fathers present age = (3x + 3) years
(3x + 3 + 3) = 2 (x + 3) + 10
3x + 6 = 2x + 16
x = 10.
Hence, fathers present age = (3x + 3) = ((3 * 10) + 3) Years= 33 Years
Let the sons present age be x years. Then, fathers present age = (3x + 3) years
(3x + 3 + 3) = 2 (x + 3) + 10
3x + 6 = 2x + 16
x = 10.
Hence, fathers present age = (3x + 3) = ((3 * 10) + 3) Years= 33 Years
1338.Rohit was 4 times as old as his son 8 years ago. After 8 years, Rohit will be twice as old as
his son. What are their present ages?
his son. What are their present ages?
40
45
42
43
Explanation:
Let sons age 8 years ago be x years. Then, Rohits age 8 years ago = 4x years.
Sons age after 8 years = (x + 8) + 8 = (x + 16) years.
Rohits age after 8 years = (4x + 8) + 8 = (4x+ 16) years.
2 (x + 16) = 4x + 16
2x = 16 => x = 8.
Hence, sons present age = (x + 8) = 16 years.
Rohits present age = (4x + 8) = 40 years
Let sons age 8 years ago be x years. Then, Rohits age 8 years ago = 4x years.
Sons age after 8 years = (x + 8) + 8 = (x + 16) years.
Rohits age after 8 years = (4x + 8) + 8 = (4x+ 16) years.
2 (x + 16) = 4x + 16
2x = 16 => x = 8.
Hence, sons present age = (x + 8) = 16 years.
Rohits present age = (4x + 8) = 40 years
1339.One year ago, the ratio of Gauravs and Sachins age was 6: 7 respectively. Four years
hence, this ratio would become 7: 8. How old is Sa chin ?
hence, this ratio would become 7: 8. How old is Sa chin ?
26 Years
36 Years
40 Years
50 Years
Explanation:
Let Gauravs and Sachins ages one year ago be 6x and 7x years respectively.
Then, Gauravs age 4 years hence = (6x + 1) + 4 = (6x + 5) years.
Sachins age 4 years hence = (7x + 1) + 4 = (7x + 5) years.
(6x+5): (7x + 5) = 7:8
8(6x+5) = 7 (7x + 5)
48x + 40 = 49x + 35
x = 5.
Hence, Sachins present age = (7x + 1) = 36 years.
Let Gauravs and Sachins ages one year ago be 6x and 7x years respectively.
Then, Gauravs age 4 years hence = (6x + 1) + 4 = (6x + 5) years.
Sachins age 4 years hence = (7x + 1) + 4 = (7x + 5) years.
(6x+5): (7x + 5) = 7:8
8(6x+5) = 7 (7x + 5)
48x + 40 = 49x + 35
x = 5.
Hence, Sachins present age = (7x + 1) = 36 years.
1340.The Ratio of Ages of Mona and Sona is 4:5. Twelve Years hence, their ages will be in the
ratio of 5:6. What will be Sonas age after 6 years ?
ratio of 5:6. What will be Sonas age after 6 years ?
40 Years
50 Years
36 Years
66 years
Explanation:
Let their present ages be 4x & 6x
Then (4x + 12)/(5x + 12) = 5/6 or x=12
Sonas age after 6 years = (5x +6) = 66 years
Let their present ages be 4x & 6x
Then (4x + 12)/(5x + 12) = 5/6 or x=12
Sonas age after 6 years = (5x +6) = 66 years
1341.Ramu was 4 times as old as his son 8 years ago. After 8 years, Ramu will be twice as old
as his son. What their present ages ?
as his son. What their present ages ?
36 years
66 years
40 Years
50 Years
Explanation:
Let sons age 8 years ago be x years
Then Ramus age at that time = 4x years
Sons age after 8 years = (x +8) + 8 = (x + 16) years
Ramus age after 8 years = (4x + 8) + 8 = (4x + 16) years
2(x + 16) = 4x + 16 or x=8
Sons present age = (x + 8) = 16 years
Ramus present age= (4x + 8) = 40 years
Let sons age 8 years ago be x years
Then Ramus age at that time = 4x years
Sons age after 8 years = (x +8) + 8 = (x + 16) years
Ramus age after 8 years = (4x + 8) + 8 = (4x + 16) years
2(x + 16) = 4x + 16 or x=8
Sons present age = (x + 8) = 16 years
Ramus present age= (4x + 8) = 40 years
1342.A man is four times as old as his son. Five years ago, the man was nine times as old his
son was at that time. What is the present age of a man ?
son was at that time. What is the present age of a man ?
66 years
40 Years
50 Years
35 years
Explanation:
Let sons age = x, then mans age =4x.
9(x - 5) = (4x-5) or x=8.
Mans present age = (4x + 7) = 35 years
Let sons age = x, then mans age =4x.
9(x - 5) = (4x-5) or x=8.
Mans present age = (4x + 7) = 35 years
1343.The sum of ages of Aruna and her mother is 49 years. Also, 7 years ago, the mothers
age was 4 times Arunas age. Find the present age of Arunas mother.
age was 4 times Arunas age. Find the present age of Arunas mother.
35 years
40 Years
50 Years
30 Years
Explanation:
Let Arunas age 7 years ago be x.
Mothers age 7 years ago = 4x
(x + 7) + (4x + 7) =49 or x=7
Mothers present age = (4x + 7) = 35 years
Let Arunas age 7 years ago be x.
Mothers age 7 years ago = 4x
(x + 7) + (4x + 7) =49 or x=7
Mothers present age = (4x + 7) = 35 years
1344.The ages of A and B differ by 16 years. If 6 years ago, the elder one be 3 times as old as
the younger one, find their present ages.
the younger one, find their present ages.
40 Years
50 Years
30 Years
35 years
Explanation:
Let As age = x & Bs age = (x + 16)
3(x - 6) = (x + 16 - 6) or x=14
As age = 14 years & Bs age = 30 years.
Let As age = x & Bs age = (x + 16)
3(x - 6) = (x + 16 - 6) or x=14
As age = 14 years & Bs age = 30 years.
1345.In three more years, Miguels grandfather will be six times as old as Miguel was last
year. When Miguels present age is added to his grandfathers present age, the total is 68.
How old is each one now?
year. When Miguels present age is added to his grandfathers present age, the total is 68.
How old is each one now?
11 years
12 years
10 years
15 years
Explanation:
Miguels present age be "m"
Grandfathers present age be "g"
Then m + g = 68
Miguels age "last year" was m – 1
His grandfathers age "in three more years" will be g + 3
The grandfathers "age three years from now" is six times Miguels "age last year"
i.e., g + 3 = 6(m – 1)
This gives me two equations with two variables:
m + g = 68
g + 3 = 6(m – 1)
Solving the first equation,
m = 68 – g
g + 3 = 6m – 6
g + 3 = 6(68 – g) – 6
g + 3 = 408 – 6g – 6
g + 3 = 402 – 6g
g + 6g = 402 – 3
7g = 399
g = 57
Since "g" stands for the grandfathers current age, then the grandfather is 57.
Since m + g = 68,
then m = 11
Miguel is presently eleven years old
Miguels present age be "m"
Grandfathers present age be "g"
Then m + g = 68
Miguels age "last year" was m – 1
His grandfathers age "in three more years" will be g + 3
The grandfathers "age three years from now" is six times Miguels "age last year"
i.e., g + 3 = 6(m – 1)
This gives me two equations with two variables:
m + g = 68
g + 3 = 6(m – 1)
Solving the first equation,
m = 68 – g
g + 3 = 6m – 6
g + 3 = 6(68 – g) – 6
g + 3 = 408 – 6g – 6
g + 3 = 402 – 6g
g + 6g = 402 – 3
7g = 399
g = 57
Since "g" stands for the grandfathers current age, then the grandfather is 57.
Since m + g = 68,
then m = 11
Miguel is presently eleven years old
1407.Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anands present age in years?
24
27
40
None of these
Explanation:
The present ages fo Sameer and Anand are in the ratio = 5 : 4
Let the present age of Sameer be 5x
Let the present age of Anand be 4x
Given : 3 years after, the ratio of ages = 11 : 9
5x +3 = 11 : 4x +3 = 9
x = 11/9
9 (5x +3 ) = 11 (4x +3 )
45x + 27 = 44x + 33
45x – 44x = 33 – 27
X = 6
To find : Anands Present age (4x = ?)
4 (6) = 24 years
The present ages fo Sameer and Anand are in the ratio = 5 : 4
Let the present age of Sameer be 5x
Let the present age of Anand be 4x
Given : 3 years after, the ratio of ages = 11 : 9
5x +3 = 11 : 4x +3 = 9
x = 11/9
9 (5x +3 ) = 11 (4x +3 )
45x + 27 = 44x + 33
45x – 44x = 33 – 27
X = 6
To find : Anands Present age (4x = ?)
4 (6) = 24 years
2903.Sachins age after 15 years will be 5 times his age 5 years back. Find out the present age of Sachin?
10 years
11 years
12 years
13 years
Explanation:
Let the present age of Sachin = $x$
Then $\left(x + 15\right)$ = 5$\left(x-5\right)$
=> 4$x$ = 40
=> $x$ = 10