See the following figure:
As the shadow reaches from point D to C towards the direction of the tree, the angle of elevation increases from 30° to 60°.
Say x is the height of the building.
a is a point 30 m away from the foot of the building.
Here, height is the perpendicular and distance between point a and foot of building is the base.
The angle of elevation formed is 30°.
Hence, tan 30° = $\dfrac{perpendicular}{base}$ = $\dfrac{x}{30}$
$\dfrac{1}{\sqrt{3}}$ = $\dfrac{x}{30}$
x =$ \dfrac{30}{\sqrt{3}}$
We know, for an angle of elevation θ,
tan θ = $\dfrac{Height of building}{Distance from the point}$
If we increase both the value of the angle of elevation remains unchanged.
As per the given question:
Hence,
tan θ = $\dfrac{6}{2\sqrt{3}}$
tan θ = $\sqrt{3}$
tan θ = tan 60°
⇒ θ = 60°
The angle formed by the line of sight with the horizontal when the point is below the horizontal level is called angle of depression.
The angle formed by the line of sight with the horizontal when the point being viewed is above the horizontal level is called angle of elevation.
We know:
tan (angle of elevation) = height of tower/its distance from the point
tan 60° = $\dfrac{h}{15}$
$\sqrt{3}$ = $\dfrac{h}{15}$
h = 15$\sqrt{3}$
The line drawn from the eye of an observer to the point in the object viewed by the observer is said to be line of sight.
The height or length of an object or the distance between two distant objects can be determined with the help of trigonometry ratios.
If the angles of elevation of the top of a tower from two points at the distance of a m and b m from the base of tower and in the same straight line with it are complementary, then the height of the tower (in m) is $\sqrt{ab}$