If $log_{4}x+log_{2}x$=12, then x is equal to:
$log_{4}x+log_{2}x$=12
=>$\dfrac{log\:x}{log\:4}+\dfrac{log\:x}{log\:2}$=12
=>$\dfrac{log\:x}{log\:2^2}+\dfrac{log\:x}{log\:2}$=12
=>$\dfrac{log\:x}{2\:log\:2}+\dfrac{log\:x}{log\:2}$=12
=>$\dfrac{log\:x+2\:log\:x}{2\:log\:2}$=12
=>$\dfrac{3\:log\:x}{2\:log\:2}$=12
Therefore,
logx=$\dfrac{12\times2\:log\:2}{3}$
=8 log 2
=$log(2^8)$
=log(256)
x=256
|
$log_{(.001)} (100)$ = ? |
Answer |
|
$(log_{3} 4)$ $(log_{4} 5)$ $(log_{5} 6)$ $(log_{6} 7)$ $(log_{7} 8)$ $(log_{8} 9)$$ (log_{9} 9)$ = ? |
Answer |
|
If $log_{12} 27$ = a, then $log_{6} 16$ is: |
Answer |
|
$log_{a} (ab)$ = x, then $log_{b} (ab)$ is : |
Answer |
|
Find the value of $\dfrac{1}{3}log_{10}125−2log_{10}4+log_{10}32$ |
Answer |
|
Find the value of x which satisfies the given expression $[log_{10} 2 + log (4x + 1)$ = $log (x + 2) + 1]$ |
Answer |
|
Which of the following statements is not correct? |
Answer |
|
If log 2 = 0.3010 and log 3 = 0.4771, What is the value of $log_{5}1024$? |
Answer |
|
If log 2 = 0.30103 and log 3 = 0.4771, find the number of digits in $(648)^{5}$ |
Answer |
|
If $log_{4}x+log_{2}x$=12, then x is equal to: |
Answer |