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$log_{(.001)} (100)$ = ?

$\dfrac{-2}{3}$
$\dfrac{3}{2}$
$\dfrac{-3}{2}$
None of these
Explanation:

Let $log_{(.001)} (100)$ =p

$(.001)^p$=100

$\left(\dfrac{1}{1000}\right)^p$=100

$\left(\dfrac{1}{10^3}\right)^p$=$10^2$

$[\left(10\right)^{-3}]^p$=$10^2$

$\left(10\right)^{-3p}$=$10^2$

-3p=2

p=$\dfrac{-2}{3}$

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