Then Income-tax on charge allowance will be according to 30%, so:
2000 x 30/100 = Rs. 600
Now it is given that by depositing Rs.1000 per month in long-term saving, additional tax is reduced by 10%
So according to 10%, it will be:
600 x 10/100 = Rs. 60.
So, person get:
= 60 + 12% (1000)
= 60 +1000 x 12/100
= 60 + 120
= Rs. 180
So the effective interest on Rs.1,000 is Rs.180
Then the effective interest on Rs.100 will be:
= ( 180 / 1000 ) x 100
= 18 %
Increased price = x[1 + $\dfrac{25}{100}$] =$\dfrac{5x}{4}$
Reduction in price to bring it back to its original value
=$\dfrac{5x}{4}-x $ = x/4
% Reduction =$\dfrac{(x/4)}{(5x/4)} \times 100 $ =20%
hence, x+ 23x/10 = 450 x
= 450 * 10/33 = 195.65
Now, 90% of 100 = 0.90 × 100 = 90
60% of 150 = 0.60 × 150 = 90
54% of 200 = 0.54 × 200 = 108
Total marks obtained in the test = 90 + 90 + 108= 288
Total maximum marks which can be obtained = 100 + 150 + 200 = 450
So, Aggregate Percentage of Marks = 288/450 × 100 = 64%
Food→ 40%
House Rent→ 20%
Entertainment→ 10%
Conveyance→ 10%
Total expenditure = 80%
Savings = 100% - 80% =20%
20%→ 1500
1%= 1500/20
Salary (100%)->$\dfrac{1500}{20} \times 100 $
=Rs.7500
Gaurav spends 30 Rs. on food, remaining Rs. = 100 - 30 = Rs. 70
Spending on conveyance and clothes = 40% of 70 = (40/100) x 70 = Rs. 28
Remaining Rs. = 70 - 28 = Rs. 42
Saving = 50% of 42 = (50/100) x 42 =Rs. 21
Applying unitary method now,
If monthly income is 100 Rs. then saving is Rs.21 Rs.
If monthly income is 1 Rs. then saving = (21/100) Rs.
If monthly income is 18400 then saving = (21/100) x 18400
Therefore, Gaurav’s monthly saving = 21 x 184 = Rs.3864
Then, (100 - 40)% of x = 420.
$\dfrac{60}{100}x x = 420 $
=>x = $\dfrac{420 x 100}{60}$ = 700.
Let total boys are =X each student is getting pencils 20% of the total number of students
=X*20/100
=X/5 it is also equal to 605/X
or 605/X=X/5.
X^2=605*5
X=55 therefore number of pencils each student get
= 605/55
=11 pencils
Calculate the percentage of error in his result.
Since 3x / 2 = x / (2 / 3)
$ x $% of $ y $=$\left(\dfrac{x}{100}\times y \right)$=$\left(\dfrac{y}{100}\times x \right)$
Increase in 10 years = (262500 - 175000) = 87500.
Increase% =$ \left(\dfrac{875 00}{175000} \times 100\right) $% = 50%.
$\therefore$ Required average =$ \left(\dfrac{50}{10} \right) $% = 5%.
Quantity of pure acid =8×$\dfrac{20}{100}$=1.6
Let the sum paid to Y per week be Rs. $ z $.
Then, $ z $ + 120% of $ z $ = 550.
$\Rightarrow z $ +$ \dfrac{120}{100} z $ = 550
$\Rightarrow \dfrac{11}{5} z $ = 550
$\Rightarrow z $ =$ \left(\dfrac{550 \times 5}{11} \right) $ = 250.
Actual price = Rs.25 + Rs.2.50 = Rs.27.5
Saving = Rs.2.5
Saving percent
=$\dfrac{2.5}{27.5}$×100=$\dfrac{250}{27.5}$=$\dfrac{2500}{275}$=$\dfrac{100}{11}$=9$\dfrac{1}{11}$% $\approx$ 9%
Suppose originally he had $ x $ apples.
Then, (100 - 40)% of $ x $ = 420.
$\Rightarrow \dfrac{60}{100} \times x $ = 420
$\Rightarrow x $ =$ \left(\dfrac{420 \times 100}{60} \right) $ = 700.
$20$% of$ a=b \implies \dfrac{20}{100}a=b.$
$\therefore b$% of 20$=\left(\dfrac{b}{100}\times 20\right)=\left(\dfrac{20}{100}a \times \dfrac{1}{100}\times 20\right)=\dfrac{4}{100}a=4 $% of a$ $