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34692.How many numbers are divisible by 4 between 1 to 100
26
24
28
22
Explanation:

There are 25 numbers which are divisible by 4 till 100. (100/4 = 25). But we should not consider 100 as we are asked to find the numbers between 1 to 100 which are divisible by 4. So answer is 24.


34693.There are 16 people, they divide into four groups, now from those four groups select a team of three members,such that no two members in the team should belong to same group.
262
256
282
280
Explanation:

We can select any three of the 4 groups in $^4C_{3}$ ways. Now from each of these groups we can select 1 person in 4 ways.


So total ways = 4 x 4 x 4 x 4 = 256


34694.7 people have to be selected from 12 men and 3 women, Such that no two women can come together. In how many ways we can select them?
2762
2732
2772
2742
Explanation:

We can select only one woman, and remaining 6 from men.


So $^{12}C_{6} \times ^3C_{1}$ = 2772


34695.Tennis players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played?
210 games
250 games
260 games
280 games
Explanation:

We can select two teams out of 15 in $^{15}C_{2}$ ways. So each team plays with other team once. Now to play two games, we have to conduct $^{15}C_{2}$ x 2 = 210 games.


34696.7528 : 5306 :: 4673 : ?
2367
2451
2531
2489
Explanation:

As there is a difference of 2222.


7528 - 2222 = 5306.


So 4673 - 2222 = 2451


34697.$x^2-y^2$=16 and xy = 15 so find out x + y
8
6
10
12
Explanation:

$x^2-y^2 $ = 16


(x+y)(x-y) = 16


So 16 comes in following table


1 $\times$ 16, 2 $\times$ 8, 4 $\times$ 4


Using 2 x 8 equation


x+y=8 and


x-y=2


So x = 5 or 3 and y = 3 or 5


So answer is 8.


34698.Census population of a district in 1981 was 4.54 Lakhs, while in year 2001 it was 7.44 Lakhs. What was the estimated mid-year population of that district in year 2009.
8.4 Lakhs
8.6 Lakhs
8.8 Lakhs
8.2 Lakhs
Explanation:

1981 ? 4.54


2001 ? 7.44


Difference ( year ) = 20


Difference ( population ) = 2.9


So population per year = $\dfrac{20}{20}$ = 0.145


2009 ? x = ?


Hence x = 7.44 + 8 $\times$ 0.145 = 8.6 Lakhs


34699.Find the maximum value of n such that 50! is perfectly divisible by $2520^n$ .
$2520^6$
$2520^4$
$2520^8$
$2520^2$
Explanation:

2520 = $2^3 \times 3^2 \times 5 \times 7$


Here 7 is the Highest prime So find the number of 7s in 50! only.


Number of 7s in 50! =$ \left[\dfrac{50}{7}\right] +\left[ \dfrac{50}{7^2}\right]$ = 7+1 = 8


For n(max) = 8, 50! is perfectly divisible by $2520^8$


34700.A girl leaves from her home. She first walks 30 metres in North-west direction and then 30 metres in South-west direction. Next, she walks 30 metres in South-east direction. Finally, she turns towards her house. In which direction is she moving?
North-east
North-west
South-east
South-west
34701.There is well of depth 30 m and frog is at bottom of the well. He jumps 3 m in one day and falls back 2 m in the same day. How many days will it take for the frog to come out of the well?
28 days
24 days
26 days
22 days
Explanation:

Frog jumps 3 m in day & falls back 2 m at night


so,frog will be 3 - 2 = 1 m up in a day.


Thus, in 27 days it will be 27 m up


On 28th day it will be at top i.e 27 + 3 = 30 m & will not fall down.


34702.Find the next term in the given series
47, 94, 71, 142, 119, 238, _ ?
331 , 360
320 , 340
215 , 430
340 , 360
Explanation:

(47, 94) (71, 142) (119, 238) (X, Y)


47 $\times$ 2 = 94


94 - 23 = 71


71 $\times$ 2=142


142 - 23 = 119


119 $\times$ 2 = 238


238 - 23 = 215


215 $\times$ 2 = 430


So the next 2 terms are 215 , 430


34703.A train leaves Meerut at 5 a.m. and reaches Delhi at 9 a.m. Another train leaves Delhi at 7 a.m. and reaches Meerut at 10.30 a.m. At what time do the two trains travel in order to cross each other ?
6:56 am
8:58 am
7:56 am
4:54 am
Explanation:

Let the total distance be x


So the speed of 1st train is x/4 and 2nd train x/3.5


In 2 hours 1st train covers half of the total distance .


So remaining is only half of the total distance(ie x/2).


Let t be the time taken


$d\dfrac{t\times x}{4}$ +$ \dfrac{t\times x}{3.5}$ = $\dfrac{x}{2}$


t=$\dfrac{14}{15}$ i.e. 56 min


i.e. Total time taken= 2 hrs + 56 min


Time they cross each other is 7:56 am (5+2.56)


Answer 7:56 am


34704.`A` and `B` started a business in partnership investing Rs 20000/- and Rs 15000/- respectively. After six months `C` jointed them with Rs 20000/-. What will be B`s share in the total profit of Rs 25000/- earned at the end of two years from the starting of the business?
7800
7500
7600
7300
Explanation:

A:B:C =(20000$\times$ 24):(15000 $\times$ 24):(20000 $\times$ 18) = 4 : 3 : 3


B`s Share = $\dfrac{3\times25000}{4+3+3}$ = 7500


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