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A train 125 m long passes a man running at 5 km/hr in the same direction in which the train is going in 10 seconds. The speed of the train is:

45 km/hr
50 km/hr
54 km/hr
55 km/hr
Explanation:
Speed of the train relative to man =$ \left(\dfrac{125}{10} \right) $m/sec
   =$ \left(\dfrac{25}{2} \right) $m/sec.
   =$ \left(\dfrac{25}{2} \times\dfrac{18}{5} \right) $km/hr

   = 45 km/hr.

Let the speed of the train be $ x $ km/hr. Then, relative speed = $\left( x - 5\right)$ km/hr.

$\therefore x $ - 5 = 45     $\Rightarrow$     $ x $ = 50 km/hr.

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