What will be remainder when (6767 + 67) is divided by 68 ?
( x n + 1) will be divisible by ( x + 1) only when $ n $ is odd.
$\therefore$(6767 + 1) will be divisible by (67 + 1)
$\therefore$(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
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