On dividing a number by 5, we get 3 as remainder. What will the remainder when the square of the this number is divided by 5 ?
Let the number be $ x $ and on dividing $ x $ by 5, we get $ k $ as quotient and 3 as remainder.
$\therefore$ $ x $ = 5k + 3
$\Rightarrow$ $ x $2 = (5k + 3)2
= (25 k 2 + 30$ k $ + 9)
= 5(5 k 2 + 6$ k $ + 1) + 4
$\therefore$On dividing $ x $2 by 5, we get 4 as remainder.