Three unbiased coins are tossed. What is the probability of getting at most two heads?
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
$\therefore P\left(E\right) $ =$ \dfrac{n(E)}{n(S)} $=$ \dfrac{7}{8} $.
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