x3/2 : 9 = 16: $\sqrt{x}$. What is the value of x ?
$\dfrac{x^{\dfrac{3}{2}}}{9}=\dfrac{16}{x^{\dfrac{1}{2}}}$
$x^{\dfrac{3}{2}+\dfrac{1}{2}}=16\times9$
$x^{2}=16\times9$
$x=4\times3=12$
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